\\ p {Punct}在我的android应用程序中的行为(\\p{Punct} behavior in my android app)

\\ p {Punct}在我的android应用程序中的行为(\\p{Punct} behavior in my android app)

这是我的正则表达式 - “[\\w\\d\\p{Punct}]+”

在我的应用程序中\\p{Punct}是非常奇怪的行为。 根据文档（ https:///javase/7/docs/api/java/util/regex/Pattern.html ）：

\ p {Punct} - 标点符号：！“＃$％＆'（）* +， - 。/ :; <=>？@ [] ^ _`{|}〜

但在我的应用程序中，此标记始终忽略此字符：“$”，“+”，“<”，“>”，“=”，“^”，“`”，“|”，“〜”

abc!d => true abc#d => true abd$d => false abc<>d = > false

等等

我试着用

Pattern pattern = ("[\w\d\p{Punct}]+", Pattern.UICODE_CASE);

没有效果。

Anny建议我做错了什么？

PS：我为它使用TextWatcher。 我这样做：

TextWatcher textWatcher = new TextWatcher() { @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) { } @Override public void onTextChanged(CharSequence s, int start, int before, int count) { // I am checking it here // if if(!().matches("[\\w\\d\\p{Punct}]+")) => do something } @Override public void afterTextChanged(Editable s) { } 

};

当我将这个TextWatcher添加到MyEditText ：

myEditText.addTextChangedListener(textWatcher);

This is my regex – “[\\w\\d\\p{Punct}]+”

It is very strange behavior of \\p{Punct} in my app. According to the docs (https:///javase/7/docs/api/java/util/regex/Pattern.html):

\p{Punct} - Punctuation: One of !"#$%&'()*+,-./:;<=>?@[]^_`{|}~

But in my app this tag always omits this characters: “$”, “+”, “<”, “>”, “=”, “^”, “`”, ”|”, ”~”

abc!d => true abc#d => true abd$d => false abc<>d = > false

etc.

I tried to use

Pattern pattern = ("[\w\d\p{Punct}]+", Pattern.UICODE_CASE);

There was no an effect.

Anny suggesti what I am doing wrong?

P.S.: I use TextWatcher for it. I do it like this:

TextWatcher textWatcher = new TextWatcher() { @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) { } @Override public void onTextChanged(CharSequence s, int start, int before, int count) { // I am checking it here // if if(!().matches("[\\w\\d\\p{Punct}]+")) => do something } @Override public void afterTextChanged(Editable s) { } 

};

When I added this TextWatcher to MyEditText:

myEditText.addTextChangedListener(textWatcher);

最满意答案

问题是\p{Punct}与POSIX [:punct:]字符类符号相匹配，该符号还包含符号\p{S} 。

为避免匹配没有符号的字符串，您需要 ：

"^[\\w\\p{P}]+$"

另外，请注意，在Android上，默认情况下， \w ， \p{P}和\p{S}是Unicode识别的。

另外， \w已经匹配数字，没有意义将\w和\d到同一个字符类[...] 。

The issue is that \p{Punct} matches the POSIX [:punct:] character class symbols that also include symbols, \p{S}.

To avoid matching the strings without symbols you need:

"^[\\w\\p{P}]+$"

Also, note that on Android, \w, \p{P} and \p{S} are Unicode-aware by default.

Besdides, \w already matches digits, there is no point adding both \w and \d into the same character class [...].